A) 3 m/s
B) 4 m/s
C) 5 m/s
D) 12 m/s
Correct Answer: C
Solution :
Initial velocity of first body \[({{u}_{1}})=0;\] Final velocity \[({{v}_{1}})\] = 3 m/s and initial velocity of second body \[({{u}_{2}})\] = 4 m/s. We know that height \[(h)=\frac{v_{1}^{2}}{2g}=\frac{{{(3)}^{2}}}{2\times 9.8}=0.46\,m.\] Therefore velocity of the second body, \[{{y}_{2}}=\sqrt{u_{2}^{2}+2gh}=\sqrt{{{(4)}^{2}}+2\times 9.8\times 0.46}\] \[=5\text{ }m\text{/}s.\]You need to login to perform this action.
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