A) -7.53 kJ/mol
B) -398.1 kJ/mol
C) -16.1 kJ/mol
D) -602 kJ/mol
Correct Answer: D
Solution :
Heat of decomposition, \[\Delta E=m.s.\,\Delta T\] \[=1\times 1.23\times 6.12=7.5276\text{ }kJ.\] Molar heat of decomposition for\[N{{H}_{4}}N{{O}_{3}}\] \[=7.5276\times 80=602.2\text{ }kJ.\]You need to login to perform this action.
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