A) 35.67 g
B) 356.7 g
C) 432.8 g
D) 502.7 g
Correct Answer: B
Solution :
As, \[\frac{{{P}^{0}}-P}{{{P}^{0}}}=\frac{\frac{w}{m}}{\frac{w}{m}+\frac{W}{M}}\] \[{{P}^{0}}\]= vap. pressure of pure component \[P\] = vap. pressure in solution \[w\] = mass of solute, \[m\]= mol. wt. of solute \[W\]= mass of solvent, \[M\]= mol. wt. of solvent \[\Rightarrow \] \[\frac{121.8-120.2}{121.8}=\frac{\frac{15}{m}}{\frac{250}{78}}\] \[\Rightarrow \] \[m=356.265\,g\]You need to login to perform this action.
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