Solved papers for JEE Main & Advanced JEE Main Paper (Held On 10 April 2016)

done JEE Main Paper (Held On 10 April 2016) Total Questions - 1

• question_answer1) The integral \[\int{\frac{dx}{\left( 1+\sqrt{x} \right)\sqrt{x-{{x}^{2}}}}}\] is equal to (where C is a constant of integration)   JEE Main Online Paper (Held On 10 April 2016)
  A)
  \[-2\sqrt{\frac{1+\sqrt{x}}{1-\sqrt{x}}}+C\]            
  done clear
  B)
  \[-2\sqrt{\frac{1-\sqrt{x}}{1+\sqrt{x}}}+C\]
  done clear
  C)
  \[-\sqrt{\frac{1-\sqrt{x}}{1+\sqrt{x}}}+C\]   
  done clear
  D)
  \[2\sqrt{\frac{1+\sqrt{x}}{1-\sqrt{x}}}+C\]
  done clear
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