Solved papers for JEE Main & Advanced AIEEE Solved Paper-2004

done AIEEE Solved Paper-2004 Total Questions - 7

  • question_answer1) If \[\int{\frac{\sin x}{\sin (x-\alpha )}}dx\] \[=Ax+B\text{ }\log \text{ }\sin (x-\alpha )+C,\]then value of \[(A,\text{ }B)\]is

    A)
    \[(sin\text{ }\alpha ,\text{ }cos\text{ }\alpha )\]     

    B)
           (b)\[(cos\text{ }\alpha ,\text{ }sin\text{ }\alpha \text{)}\]

    C)
           \[(-\sin \text{ }\alpha ,\text{ }\cos \text{ }\alpha )\]

    D)
           \[(-\cos \text{ }\alpha ,\text{ }\sin \text{ }\alpha )\]

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  • question_answer2) With two forces acting at a point, the maximum effect is obtained when their resultant is 4N. If they act at right angles, then their resultant is 3N. Then, the forces are

    A)
    \[(2+\sqrt{2})N\]and\[(2-\sqrt{2})N\]

    B)
    \[(2+\sqrt{3})N\]and\[(2-\sqrt{3})N\]

    C)
    \[\left( 2+\frac{1}{2}\sqrt{2} \right)N\]and \[\left( 2-\frac{1}{2}\sqrt{2} \right)N\]

    D)
    \[\left( 2+\frac{1}{2}\sqrt{3} \right)N\]and\[\left( 2-\frac{1}{2}\sqrt{3} \right)N\]            

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  • question_answer3) In a right angled \[\Delta ABC,\,\,\angle A={{90}^{\text{o}}}\] and sides a,b,c are respectively, 5 cm, 4 cm and 3 cm. If a force F has moments 0, 9 and 16 (in N cm) units respectively about vertices A, B and C, the magnitude of F is

    A)
    3                             

    B)
           4                             

    C)
    5                             

    D)
           9

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  • question_answer4) Three forces P, Q and R acting along\[IA,IB\]and \[IC,\]where\[I\]is the incentre of a\[\Delta ABC,\]are in equilibrium. Then, P : Q : R is

    A)
    \[\cos \frac{A}{2}:\cos \frac{B}{2}:\cos \frac{C}{2}\]

    B)
    \[\sin \frac{A}{2}:\sin \frac{B}{2}:\sin \frac{C}{2}\]

    C)
    \[\sec \frac{A}{2}:\sec \frac{B}{2}:\sec \frac{C}{2}\]

    D)
    \[\cos ec\,\frac{A}{2}:\,\,\cos ec\,\frac{B}{2}\,:\,\cos ec\,\frac{C}{2}\]

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  • question_answer5) A particle moves towards East from a point A to a point B at the rate of 4 km/h and then towards North from B to C at rate of 5 km/h. If AB = 12 km and BC = 5 km, then its average speed for its journey from A to C and resultant average velocity direct from A to C are respectively

    A)
    \[\frac{17}{14}km/h\text{ }and\frac{13}{4}km/h\]

    B)
    \[\frac{13}{4}km/h\text{ }and\frac{17}{4}km/h\]

    C)
    \[\frac{17}{9}km/h\text{ }and\frac{13}{9}km/h\]

    D)
    \[\frac{13}{9}km/h\text{ }and\frac{17}{9}km/h\]

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  • question_answer6) A velocity 1/4 m/s is resolved into two components along OA and OB making angles \[30{}^\circ \]and\[45{}^\circ \]respectively with the given velocity, Then, the component along OB is

    A)
    \[\frac{1}{8}m/s\]           

    B)
           \[\frac{1}{4}(\sqrt{3}-1)m/s\]    

    C)
    \[\frac{1}{4}m/s\]           

    D)
           \[\frac{1}{8}(\sqrt{6}-\sqrt{2})m/s\]

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  • question_answer7) If\[{{t}_{1}}\]and\[{{t}_{2}}\]are the times of flight of two particles having the same initial velocity u and range R on the horizontal, then\[t_{1}^{2}+t_{2}^{2}\]is equal to

    A)
    \[{{u}^{2}}/g\]                                  

    B)
    \[4{{u}^{2}}/{{g}^{2}}\]                

    C)
    \[{{u}^{2}}/2g\]         

    D)
           1

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AIEEE Solved Paper-2004
 

   


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