Solved papers for JEE Main & Advanced AIEEE Solved Paper-2008

done AIEEE Solved Paper-2008 Total Questions - 2

• question_answer1) Directions: Questions No. 76 are based on the following paragraph Consider a block of conducting material of resistivity '\[\rho \]' shown in the figure. Current 'I' enters at 'A' and leaves from 'D' . We apply superposition principal to find voltage '\[\Delta V\]' developed between 'B' and 'C' .  The calculation is done in the following steps: (i) Take current 'I' entering from 'A' and assume it to spread over a hemispherical surface in the block. (ii) Calculate field E(r) at distance 'r' from A by using Ohm's law \[E=\rho j\], where 'j' is the current per unit area at 'r'. (iii) From the 'r' dependence of E(r), obtain the potential V(r) at 'r'. (iv) Repeat (i), (ii) and (iii) for current 'I' leaving 'D' and superpose results for 'A' and 'D'.        For current entering at A, the electric field at a distance 'r' from A is     AIEEE  Solved  Paper-2007
  A)
  \[\frac{\rho I}{2\pi {{r}^{2}}}\]  
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  B)
  \[\frac{\rho I}{4\pi {{r}^{2}}}\]  
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  C)
  \[\frac{\rho I}{8\pi {{r}^{2}}}\]  
  done clear
  D)
  \[\frac{\rho I}{{{r}^{2}}}\]
  done clear
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• question_answer2) A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 \[km\,{{s}^{-1}}\], the escape velocity from the surface of the planet would be
  A)
  110 \[km\,{{s}^{-1}}\]   
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  B)
         0.11 \[km\,{{s}^{-1}}\]  
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  C)
         1.1 \[km\,{{s}^{-1}}\]    
  done clear
  D)
         11 \[km\,{{s}^{-1}}\]
  done clear
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