Solved papers for JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

done JEE Main Paper (Held On 11 April 2014) Total Questions - 1

• question_answer1) The angular frequency of the damped oscillator is given by,\[\omega =\sqrt{\left( \frac{k}{m}-\frac{{{r}^{2}}}{4{{m}^{2}}} \right)}\]where k is the spring constant, m is the mass of the oscillator and r is the damping constant. If the ratio\[\frac{{{r}^{2}}}{mk}\]is 8%, the change in time period compared to the undamped oscillator is approximately as follows:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )
  A)
  increases by 1%               
  done clear
  B)
  increases by 8%
  done clear
  C)
  decreases by 1%             
  done clear
  D)
  decreases by 8%
  done clear
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