A) \[\frac{5}{3}sq\,\,unit\]
B) \[\frac{5}{4}sq\,\,unit\]
C) \[\frac{5}{12}sq\,\,unit\]
D) \[\frac{12}{5}sq\,\,unit\]
Correct Answer: C
Solution :
Solving the given curves\[y=\sqrt{x}\]or\[{{y}^{2}}=x\]and\[y={{x}^{3}}\] we get, the points of intersection (0, 0) and (1, 1). \[\therefore \]Required area\[=\int_{0}^{1}{(\sqrt{x}-{{x}^{3}})}dx\] \[=\left[ \frac{{{x}^{3/2}}}{3/2}-\frac{{{x}^{4}}}{4} \right]_{0}^{1}\]You need to login to perform this action.
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