A) zero
B) \[\frac{Qq}{4\pi G{{\varepsilon }_{0}}r}\]
C) \[\frac{Qq}{2\pi G{{\varepsilon }_{0}}r}\]
D) None of these
Correct Answer: A
Solution :
Potential due to charge\[(q)\]at point\[(r)\]is given by \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{q}{r}\]You need to login to perform this action.
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