A) equal
B) imaginary
C) real
D) None of these
Correct Answer: C
Solution :
Given, \[a+b+c=0\] Let the roots of the equation \[4a{{x}^{2}}+3bx+2c=0\]are\[\alpha \]and\[\beta \]. Now, \[D={{b}^{2}}-4ac\] \[=9{{b}^{2}}-4(4a)(2c)\] \[=9{{b}^{2}}-32ac\] \[=9{{(a+c)}^{2}}-32ac\] Hence, roots are real.You need to login to perform this action.
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