A) 281.25 N
B) 187.5N
C) 562.5 N
D) 375 N
Correct Answer: D
Solution :
If a constant force\[\overset{\to }{\mathop{F}}\,\]is applied on a body for short interval of time\[\Delta t\], then the impulse this force is\[F\times \Delta t\]. Since, impulse = change in momentum\[(\Delta p)\] \[\therefore \] \[F\times \Delta t=\Delta p\] \[\Rightarrow \] \[F=\frac{\Delta p}{\Delta t}\] Change in \[x-\]direction \[F=\frac{m[30-(-15\sin {{30}^{o}})]}{0.01}\] \[F=\frac{0.1\times 37.5}{0.01}=375\,\,N\] Note: Unit of impulse is same as that of momentum.You need to login to perform this action.
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