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Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    The decomposition of a certain mass of\[CaC{{O}_{3}}\]gave\[11.2\,\,d{{m}^{3}}\]of\[C{{O}_{2}}\]gas at STP. The mass of\[KOH\]required to completely I neutralize the gas is

    A)  56 g                                                                      

    B)  28 g                      

    C)  42 g                      

    D)         20 g

    Correct Answer: B

    Solution :

    Weight of\[11.2\,\,d{{m}^{3}}\]of\[C{{O}_{2}}\]gas at STP                 \[=44/2=22g\]       \[\underset{56\,\,g}{\mathop{KOH}}\,+\underset{44\,\,g}{\mathop{C{{O}_{2}}}}\,\xrightarrow{{}}KHC{{O}_{3}}\] \[\therefore \,\,KOH\]required for complete neutralization of\[C{{O}_{2}}(44\,\,g)=56\,\,g\] \[\therefore \,\,KOH\]required for neutralization of 22 g of \[C{{O}_{2}}=\frac{56}{44}\times 22=28\,\,g\]


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