A) \[{{y}^{2}}-8x-6y+25=0\]
B) \[{{y}^{2}}-6x+8y-25=0\]
C) \[{{x}^{2}}-6x-8y+25=0\]
D) \[{{x}^{2}}+6x-8y-25=0\]
Correct Answer: C
Solution :
Given equation can be rewritten as \[{{(y-2)}^{2}}=12x\] Here, vertex and foci are (0, 2) and (3, 2). \[\therefore \]Vertex of the required parabola is (3, 2) and focus is (3, 4). The axis of symmetry is\[x=3\]and latusrectum\[=4\cdot 2=8\] Hence, required equation is \[{{(x-3)}^{2}}=8(y-2)\] or \[{{x}^{2}}-6x-8y+25=0\]You need to login to perform this action.
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