A) \[\frac{1}{9}\]
B) \[\frac{2}{9}\]
C) \[\frac{3}{9}\]
D) \[\frac{4}{9}\]
Correct Answer: D
Solution :
Given,\[{{x}^{2}}+4x+c=0\] For real roots, \[D={{b}^{2}}-4ac\ge 0\] \[=16-4c\ge 0\] \[\Rightarrow \,\,c=1,\,\,2,\,\,3,\,\,4\]will satisfy the above inequality. \[\therefore \]Required probability\[=\frac{4}{9}\]You need to login to perform this action.
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