A) \[\Delta H=0\]
B) \[\Delta E=0\]
C) \[\Delta H=T\Delta S\]
D) \[\Delta H=\Delta E\]
Correct Answer: C
Solution :
\[\Delta G=\Delta H-T\cdot \Delta S\] For the reaction, \[{{H}_{2}}O(l){{H}_{2}}O(g)\] \[\Delta G=0\](at equilibrium) \[\therefore \] \[\Delta H=T\cdot \Delta S\]You need to login to perform this action.
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