A) 8
B) 2
C) 1
D) 3
Correct Answer: B
Solution :
Total milliequivalents of\[{{H}^{+}}\] \[=30\times \frac{1}{3}+20\times \frac{1}{2}=20\] Total milliequivalents of\[O{{H}^{-}}\] \[=40\times \frac{1}{4}=10\] Milli equivalence of \[{{H}^{+}}\] left \[=20-10=10\] \[\therefore \] \[[{{H}^{+}}]=\frac{10}{1000}g\,\,ions/d{{m}^{3}}={{10}^{-2}}\] \[\therefore \] \[pH=2\]You need to login to perform this action.
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