A) 10\[\Omega \]
B) 200\[\Omega \]
C) 80\[\Omega \]
D) 50\[\Omega \]
Correct Answer: A
Solution :
Givers-galvanometer resistance\[G=240\Omega \] Shunt resistance\[S=?\] \[{{I}_{G}}=\frac{4}{100}I\] From figure voltage through the circuit. \[(I-{{I}_{G}})S={{I}_{G}}G\] or \[\left( 1-\frac{4I}{100} \right)S=\frac{4I}{100}\times 240\] or \[S=\frac{4\times 240}{96}=10\Omega \]You need to login to perform this action.
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