A) \[+184\,\,kJ\]
B) \[+23\,\,kJ\]
C) \[+92\,\,kJ\]
D) \[+46\,\,kJ\]
Correct Answer: C
Solution :
\[2N{{H}_{3}}(g)\xrightarrow{{}}{{N}_{2}}(g)+3{{H}_{2}}(g)\] \[\Delta {{H}_{r}}=-\](\[2\times \]enthalpy of formation of\[N{{H}_{3}}\]) \[=-(2\times -46)=92\,\,kJ\]You need to login to perform this action.
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