A) \[\frac{a\sin \beta \cdot \sin \gamma }{\sin \alpha \cdot \sin (\alpha +\beta +\gamma )}\]
B) \[\frac{a\sin \alpha \cdot \sin \gamma }{\sin \beta \cdot \sin (\alpha +\beta +\gamma )}\]
C) \[\frac{a\sin \alpha \cdot \sin \beta }{\sin \gamma \cdot \sin (\alpha +\beta +\gamma )}\]
D) None of the above
Correct Answer: B
Solution :
Clearly, \[\angle CDA=\beta ,\,\,\angle DCB=\gamma ,\,\,\angle ACB=\pi -(\alpha +\beta +\gamma )\]Using since rule in \[\Delta \,CAB,\] we getYou need to login to perform this action.
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