A) 80
B) 120
C) 40
D) 280
Correct Answer: D
Solution :
\[{{E}_{a}}(B\to A)=80\,\,kJ\,\,mo{{l}^{-1}}\] Heat of reaction\[(A\to B)=200kJ\,\,mo{{l}^{-1}}\] For\[(B\to A)\]backward reaction, \[{{E}_{a}}(B\to A)={{E}_{a}}(A\to B)+\]heat of reaction \[=80+200=280\,\,kJ\,\,mo{{l}^{-1}}\]You need to login to perform this action.
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