A) 139.5
B) 203
C) 279
D) 101.5
Correct Answer: A
Solution :
Equivalence conductance = conducting power of all the ion produced by one gram equivalent of an electrolyte. Since, Eq. wt. of\[BaC{{l}_{2}}=\frac{mol.wt.}{2}\]then \[\lambda _{BaC{{l}_{2}}}^{\infty }=\frac{1}{2}{{\lambda }^{\infty }}B{{a}^{2+}}+{{\lambda }^{\infty }}C{{l}^{-}}\] \[=\frac{127}{2}+76\] \[=139.5\,\,oh{{m}^{-1}}c{{m}^{2}}\]You need to login to perform this action.
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