A) \[3.2\times {{10}^{10}}\]
B) \[0.53\times {{10}^{10}}\]
C) \[2.1\times {{10}^{10}}\]
D) \[0.8\times {{10}^{10}}\]
Correct Answer: D
Solution :
Remaining amount\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[N=6.4\times {{10}^{10}}{{\left( \frac{1}{2} \right)}^{12/4}}\] \[=0.8\times {{10}^{10}}\,\,atoms\]You need to login to perform this action.
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