A) \[{{0}^{o}}C\]
B) \[{{27}^{o}}C\]
C) \[-{{99}^{o}}C\]
D) \[-{{200}^{o}}C\]
Correct Answer: C
Solution :
Let RMS speed of nitrogen at\[T\,\,\,K\]be\[u\]and is equal to that of\[C{{O}_{2}}\]at\[STP\] \[u=\sqrt{\frac{3RT}{28}}=\sqrt{\frac{3R\times 273}{44}}\] \[T=\frac{273\times 28}{44}=173.73K=-{{99.27}^{o}}C\]You need to login to perform this action.
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