A) 0
B) 1
C) 2
D) 3
Correct Answer: B
Solution :
Given that,\[{{\log }_{4}}(x-1)={{\log }_{2}}(x-3)\] \[\therefore \] \[x-1={{(x-3)}^{2}}\] \[\Rightarrow \] \[{{x}^{2}}-7x+10=0\] \[\Rightarrow \] \[(x-5)(x-2)=0\] \[\Rightarrow \] \[x=2,\,\,5\] \[\Rightarrow \]\[x=5\], but\[x=2{{\log }_{2}}(x-3)\]is not satisfied.You need to login to perform this action.
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