A) \[0\]
B) \[y\,\,\mathbf{j}\]
C) \[-z\,\,\mathbf{i}+x\,\,\mathbf{k}\]
D) \[z\,\,\mathbf{i}-x\,\,\mathbf{k}\]
Correct Answer: D
Solution :
Since,\[\mathbf{a,}\,\,\mathbf{b,}\,\,\mathbf{c}\]form a right handed system \[\therefore \] \[\mathbf{c}=\mathbf{b}\times \mathbf{a}\] \[=\mathbf{j}\times (x\mathbf{i}+y\mathbf{j}+z\mathbf{k})\] \[=x(\mathbf{j}\times \mathbf{i})+z(\mathbf{j}\times \mathbf{k})\] \[=-x\mathbf{k}+z\mathbf{i}=z\mathbf{i}-x\mathbf{k}\]You need to login to perform this action.
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