A) \[0\]
B) \[abc\]
C) \[a+b+c\]
D) \[ab+bc+ca\]
Correct Answer: A
Solution :
Now, \[\frac{b-c}{{{r}_{1}}}+\frac{c-a}{{{r}_{2}}}+\frac{a-b}{{{r}_{3}}}\] \[=\frac{[(b-c)(s-a)+(c-a)(s-b)+(a-b)(s-c)]}{\Delta }\] \[=0\]You need to login to perform this action.
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