A) \[1\]
B) \[2\]
C) \[9/4\]
D) \[-1/4\]
Correct Answer: B
Solution :
Given that, \[\frac{2x+3}{(x+1)(x-3)}=\frac{a}{(x+1)}+\frac{b}{(x-3)}\] \[\Rightarrow \] \[(2x+3)=a(x-3)+b(x+1)\] On comparing the coefficient of\[x\]and constant, we get \[2=a+b\]and\[3=-3a+b\] \[\Rightarrow \] \[a=-\frac{1}{4}\]and\[b=\frac{9}{4}\] \[\therefore \] \[a+b=-\frac{1}{4}+\frac{9}{4}=2\]You need to login to perform this action.
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