A) 16 L
B) 64 L
C) \[\frac{L}{4}\]
D) 4 L
Correct Answer: D
Solution :
\[L=mvr=m\sqrt{\frac{GM}{r}}r=m\sqrt{GMr}\] \[\therefore \] \[L\propto \sqrt{r}\] \[\Rightarrow \] \[\frac{{{L}_{2}}}{{{L}_{1}}}=\sqrt{\frac{{{r}_{2}}}{{{r}_{1}}}}\] \[=\sqrt{\frac{16r}{r}}=4\] \[\Rightarrow \] \[{{L}_{2}}=4L\]You need to login to perform this action.
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