A) 20 N
B) 40 N
C) 10 N
D) 32 N
Correct Answer: D
Solution :
\[{{T}_{2}}=\frac{({{m}_{1}}+{{m}_{2}}){{T}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] \[=\frac{(10+6)\times 40}{10+6+4}\] \[=\frac{16\times 40}{20}\] \[=32\,\,N\]You need to login to perform this action.
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