Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    In an explosion a body breaks up into pieces of unequal masses. In this case

    A)  both parts will have numerically equal momentum

    B)  lighter part will have more momentum

    C)  heavier part will have more momentum

    D)  both parts will have equal kinetic energy

    Correct Answer: D

    Solution :

    From law of conservation of linear momentum i.e., final momentum = initial momentum                 \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}=0\]                                        ... (i) where\[{{m}_{1}}\]and\[{{m}_{2}}\]are masses of pieces. (initial momentum is zero because body is stationary) From Eq. (i),\[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}\] So, numerical value of momentum of both pieces will be equal.


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