A) 16
B) 48
C) 64
D) 32
Correct Answer: A
Solution :
\[S{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}3S+2{{H}_{2}}O\] Eq. wt. of\[S{{O}_{2}}\]in the reaction \[=\frac{molar\,\,mass\,\,of\,\,S{{O}_{2}}}{change\,\,in\,\,oxidation\,\,state}=\frac{64}{4}=16\]You need to login to perform this action.
You will be redirected in
3 sec