A) 0.12 mm
B) 0.3 mm
C) 3.0 mm
D) 4.0 mm
Correct Answer: B
Solution :
Separation of slits\[d=4\,\,mm=4\times {{10}^{-3}}m\] Wavelength\[\lambda =6000\overset{\text{o}}{\mathop{\text{A}}}\,=6\times {{10}^{-7}}m\] Distance of screen\[D=2\,\,m\] Fringe width\[\beta =\frac{\lambda D}{d}\] \[=\frac{6\times {{10}^{-7}}\times 2}{4\times {{10}^{-3}}}\] \[=3\times {{10}^{-4}}m\] \[=0.3\,\,mm\]
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