A) 0.15 V
B) 1.5 V
C) 0.15 mV
D) 1.5 mV
Correct Answer: D
Solution :
Given,\[l=10\,\,m,\,\,v=5\,\,m/s\] and \[H=0.3\times {{10}^{-4}}\,\,Wb/{{m}^{2}}\] Induced\[emf\,\,e=Hvl\] \[=0.3\times {{10}^{-4}}\times 5\times 10\] \[=1.5\times {{10}^{-3}}\,\,V\] \[=1.5\,\,m\,\,V\]You need to login to perform this action.
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