A) \[\frac{17}{4}sq\,\,units\]
B) \[\frac{1}{4}sq\,\,unit\]
C) \[4\,\,sq\,\,units\]
D) None of these
Correct Answer: A
Solution :
Required area\[=\int_{-1}^{2}{|{{x}_{1}}|dy}\] \[=\int_{-1}^{0}{(-{{x}_{1}})dy+\int_{0}^{2}{{{x}_{1}}dy}}\] \[=-\int_{-1}^{0}{{{y}^{3}}dy+\int_{0}^{2}{{{y}^{3}}dy}}\] \[=-\left[ \frac{{{y}^{4}}}{4} \right]_{-1}^{0}+\left[ \frac{{{y}^{4}}}{4} \right]_{0}^{2}=\frac{1}{4}+4\] \[=\frac{17}{4}\,\,sq\,\,units\].You need to login to perform this action.
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