A) 0
B) 1
C) 2
D) None of these
Correct Answer: A
Solution :
Given that,\[x={{(2t-3)}^{2}}\] On differentiating w.r.t.\[x\], we get \[\frac{dx}{dt}=2(2t-3)(2)\] At origin,\[x=0\] \[\therefore \] \[2t-3=0\] \[\Rightarrow \] \[t=\frac{3}{2}\] \[\therefore \] Velocity\[=\frac{dx}{dt}=4\left( 2\times \frac{3}{2}-3 \right)=0\]You need to login to perform this action.
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