A) 3
B) 5
C) 7
D) 9
Correct Answer: B
Solution :
\[D={{360}^{o}}-2\theta \] \[\Rightarrow \] \[{{240}^{o}}={{360}^{o}}-2\theta \] \[2\theta ={{120}^{o}}\], \[\therefore \,\,\theta ={{60}^{o}}\] Then, number of images observable \[N=\frac{{{360}^{o}}}{{{60}^{o}}}-1\] \[N=6-1\] \[N=5\]You need to login to perform this action.
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