A) 23
B) 3
C) 43
D) 4.3
Correct Answer: C
Solution :
\[L=10{{\log }_{10}}\left( \frac{I}{{{I}_{0}}} \right)\] \[\therefore \] \[L=10{{\log }_{10}}\left( \frac{2\times {{10}^{-8}}}{{{10}^{-12}}} \right)\] \[(\because \,\,{{I}_{0}}={{10}^{-12}}W/{{m}^{2}})\] \[L=10{{\log }_{10}}(2\times {{10}^{4}})\] \[L=10[{{\log }_{10}}2+{{\log }_{10}}{{(10)}^{4}}]\] \[L=10(4.3)\] \[L=43\,\,decibel\]You need to login to perform this action.
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