A voltmeter of resistance\[998\Omega \]is connected across a cell of emf\[2\,\,V\]and internal resistance\[2\Omega \]. The potential difference across the voltmeter is
A)\[1.99\,\,V\]
B)\[3.5\,\,V\]
C)\[5\,\,V\]
D) \[6\,\,V\]
Correct Answer:
A
Solution :
From Ohms law \[i=\frac{E}{R+r}=\frac{2}{998+2}=2\times {{10}^{-3}}A\] Potential difference across the voltmeter is \[V=iR=(2\times {{10}^{-3}})\times 998\] \[=1996\,V\]