A) \[3\,\,kJ\,\,mo{{l}^{-1}}\]
B) \[4\,\,kJ\,\,mo{{l}^{-1}}\]
C) \[5\,\,kJ\,\,mo{{l}^{-1}}\]
D) \[6\,\,kJ\,\,mo{{l}^{-1}}\]
Correct Answer: D
Solution :
\[\because \]\[\Delta G=\Delta \Eta -\Tau \Delta S\] At equilibrium,\[\Delta G=0\] \[\therefore \] \[\Delta H=T\Delta S\] \[\Delta H=273\times (60.01-38.20)\] \[=5954.13\,\,J\,\,mo{{l}^{-1}}=5.954\,\,kJ\,\,mo{{l}^{-1}}\] \[\approx 6\,\,kJ\,\,mo{{l}^{-1}}\]You need to login to perform this action.
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