A) 46%
B) 53%
C) 75%
D) 92%
Correct Answer: B
Solution :
The reaction is \[{{N}_{2}}{{O}_{4}}2N{{O}_{2}}\] Molecular weight of\[{{N}_{2}}{{O}_{4}}=2\times 14+4\times 16\] \[=92\] \[\therefore \]Vapour density\[(D)\]of\[{{N}_{2}}{{O}_{4}}\] \[=\frac{molecular\,\,weight}{2}\] \[=\frac{92}{2}=46\] From, \[\alpha =\frac{D-d}{(n-1)d}\] \[\alpha =\frac{46-30}{(2-1)30}=\frac{16}{30}\] \[=0.533=53.3%\]You need to login to perform this action.
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