A) \[94,\,\,230\]
B) \[232,\,\,90\]
C) \[190,\,\,32\]
D) \[230,\,\,94\]
Correct Answer: B
Solution :
The decay equation is \[_{92}{{X}^{A}}{{\to }_{Z}}{{Y}^{228}}+\alpha \] \[\alpha -\]particle is nucleus of\[_{2}H{{e}^{4}}\] \[_{92}{{X}^{A}}{{\to }_{Z}}{{Y}^{228}}{{+}_{2}}H{{e}^{4}}\] \[A=228+4=232\] \[Z=92-2=90\]You need to login to perform this action.
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