A) 4
B) 2
C) either 4 or 2
D) None of these
Correct Answer: A
Solution :
We know that, in a square matrix of order n \[|adjA|=|A{{|}^{n-1}}\] \[\Rightarrow \] \[|adj(adj\,\,A)|=|adj\,\,A{{|}^{n-1}}=|A{{|}^{{{(n-1)}^{2}}}}\] \[\Rightarrow \] \[{{n}^{2}}-2n-8=0\] \[\Rightarrow \] \[n=4\]as\[n=-2\]is not possible.You need to login to perform this action.
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