A) \[m=1,\,\,n=1\]
B) \[m=1,\,\,n=2\]
C) \[m=2,\,\,n=1\]
D) \[m=2,\,\,n=2\]
Correct Answer: B
Solution :
Position\[x=K{{a}^{m}}{{t}^{n}}\] Writing the dimension on the both sides. \[[{{M}^{0}}L\,\,{{T}^{0}}]={{[L\,\,{{T}^{-2}}]}^{m}}{{[T]}^{n}}\] \[[{{M}^{0}}{{L}^{m}}{{T}^{-2m+n}}]\] On comparing both sides. \[m=1\] \[-2m+n=0\] \[n=2m=2\times 1=2\]You need to login to perform this action.
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