A) \[12Hz\]
B) \[25Hz\]
C) \[10Hz\]
D) \[5Hz\]
Correct Answer: C
Solution :
\[F=mr\,\,{{\omega }^{2}}=mr\times {{(2\pi mm)}^{2}}=4{{\pi }^{2}}m{{m}^{2}}\] \[F\propto 2{{n}^{2}}\] \[F={{F}_{1}}+{{F}_{2}}\] \[{{n}^{2}}=n_{1}^{2}+n_{2}^{2}\] \[n=\sqrt{n_{1}^{2}+n_{2}^{2}}\] \[n=\sqrt{{{(6)}^{2}}+{{(8)}^{2}}}\] \[n=\sqrt{100}=10\,\,Hz\]You need to login to perform this action.
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