A) 1 mm
B) 3 mm
C) 6 mm
D) 9 mm
Correct Answer: D
Solution :
The narrower the tube, the higher is the rise in water. when a glass capillary \[h=\frac{2T\cos \theta }{R\rho g}\] \[h\propto \frac{1}{R}\] \[\frac{{{h}_{1}}}{{{h}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}\] \[\frac{3}{{{h}_{2}}}=\frac{1}{3}\] \[{{h}_{2}}=9mm\]You need to login to perform this action.
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