A) \[P=\pm 1\]
B) \[P=\pm 2\]
C) \[P=\pm \frac{1}{2}\]
D) None of these
Correct Answer: C
Solution :
\[\frac{dy}{dx}=P{{e}^{px}}+P\] \[{{\left( \frac{dy}{dx} \right)}_{(0,\,\,1)}}=2P\] Subtangent\[=\left| y\frac{dx}{dy} \right|\], subnormal\[=\left| y\frac{dy}{dx} \right|\] Given; Subtangent = Subnormal \[\Rightarrow \]\[\frac{dy}{dx}=\pm 1\,\,\Rightarrow \,\,2p=\pm 1\] \[\Rightarrow \] \[p=\pm \frac{1}{2}\]You need to login to perform this action.
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