Manipal Engineering Manipal Engineering Solved Paper-2014

  • question_answer
    The equation \[8{{x}^{2}}-26x+15=0,\]constant. The unit of a is

    A) Dyne \[\cos (\alpha +\beta )\]                  

    B) Dyne \[\frac{627}{725}\]

    C) Dyne\[\frac{627}{725}\]               

    D)  Dyne\[a{{\cos }^{3}}\alpha +3a\cos \alpha {{\sin }^{2}}\alpha =m\]

    Correct Answer: B

    Solution :

     According to the principle of dimensional homogenity \[\propto \frac{\text{1}}{\text{Bond}\,\text{order}}\] \[C{{F}^{+}}<CF<C{{F}^{-}}.\]\[{{N}_{2}}O={{O}_{2}}=0.05M\] Hence, the units of \[N{{O}_{2}}\]\[{{K}_{C}}=0.917=\frac{{{(0.05)}^{2}}}{{{x}^{2}}}\Rightarrow x=0.0522M\]


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