A) 1 : 2 : 3
B) 1 : 4 : 9
C) 4 : 9 : 36
D) 3 : 2 : 1
Correct Answer: C
Solution :
Using\[R\sqrt{\frac{2}{15}}\]\[g\left( =\frac{4{{\pi }^{2}}l}{{{T}^{2}}} \right),l\approx 1m,\]
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