A) L/5
B) 4L/5
C) 3L/4
D) L/4
Correct Answer: A
Solution :
\[{{S}_{4}}O_{6}^{2-}\] \[C{{l}_{2}}{{O}_{7}}\] For rotational equilibrium,\[CC{{l}_{4}}\]\[CC{{l}_{4}}\]\[\text{(a}\,\text{=}\,\text{20}{{\text{L}}^{\text{2}}}\text{mo}{{\text{l}}^{\text{-2}}}\text{atm}\,\text{and}\,\text{b}\ \text{=}\,\text{0}\text{.14}\,\text{L}\,\text{mo}{{\text{l}}^{\text{-1}}}\text{)}\]You need to login to perform this action.
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