question_answer

Ratio of area of hole to beaker is 0.1. Height of liquid in beaker is 3m, and hole is at the height of 52.5 cm from the bottom of beaker, find the square of the velocity of liquid coming out from the hole

A) \[4{{x}^{2}}+2{{y}^{2}}-9x=0\]                  

B) \[|a|=1,|b|=4,a.b=2\]

C) \[c=2a\times b-3b,\]                     

D) \[\frac{\pi }{6}\]

Correct Answer: A

Solution :

                \[5B{{r}^{-}}(aq)+BrO_{3}^{-}(aq)+6{{H}^{+}}(aq)\xrightarrow[{}]{{}}3B{{r}_{2}}(aq)\]